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The lengths of pregnancy terms for a particular species of mammal are nearly normally distributed about...
Problem 4 [6 points] When a woman learns she is pregnant, her doctor usually calculates a...
Problem 4 [6 points] When a woman learns she is pregnant, her doctor usually calculates a "due date" for the baby. The due date represents the date on which the baby will be born if her pregnancy lasts the mean length for all pregnancies. Actual lengths of pregnancy terms turn out to be nearly normally distributed about this due date (the mean) with a standard deviation of 15 days a. About what percentage of births occur within 15 days of...
not sure about this one any help would be appreciated! The lengths of pregnancies are normally...
not sure about this one any help would be appreciated!
The lengths of pregnancies are normally distributed with a mean of 267 days and a standard deviation of 15 days. a. Find the probability of a pregnancy lasting 309 days or longer b If the length of pregnancy is in the lowest 4%, then the baby is premature Find the length that separates premature babies from those who are not premature a. The probability that a pregnancy will last 309...
The lengths of pregnancies are normally distributed with a mean of 268 days and a standard...
The lengths of pregnancies are normally distributed with a mean of 268 days and a standard deviation of 15 days. a. Find the probability of a pregnancy lasting 309 days or longer. b. If the length of pregnancy is in the lowest 4%, then the baby is premature. Find the length that separates premature babies from those who are not premature. Click to view page 1 of the table. Click to view page 2 of the table. a. The probability...
EQuestion Help The lengths of pregnancies are normally distributed with a mean of 267 days and...
EQuestion Help The lengths of pregnancies are normally distributed with a mean of 267 days and a standard deviation of 15 days. a. Find the probability of a pregnancy lasting 309 days or longer b. If the length of pregnancy is in the lowest 4%, then the baby is premature. Find the length that separates premature babies tom those who are a. The probability that a pregnancy will last 309 days or longer is (Round to four decimal places as...
1. The lengths of pregnancies are normally distributed with a mean of 268 days and a...
1. The lengths of pregnancies are normally distributed with a mean of 268 days and a standard deviation of 15 days. a) Find the 80th percentile of pregnancy length. b) Find the pregnancy length that separates the upper 30% c) Find the pregnancy lengths that separate the middle 80% d) Find the percent of pregnancies that are less than 260 days. e) Find the percent of pregnancies that are between 250 and 280 days
6.2.31 Question Help The lengths of pregnancies are normally distributed with a mean of 268 days...
6.2.31 Question Help The lengths of pregnancies are normally distributed with a mean of 268 days and a standard deviation of 15 days. a. Find the probability of a pregnancy lasting 309 days or longer b. If the length of pregnancy is in the lowest 3%, then the baby is premature. Find the length that separates premature babies from those who are not premature Click to view page 1 of the table, Click to view,page 2 of the table a....
A population of adult gastropods of the colourful species Cypraea tigris have normally distributed lengths with...
A population of adult gastropods of the colourful species Cypraea tigris have normally distributed lengths with a mean of 9.8 cm and a standard deviation of 1.7 cm. Determine the percentage of adults of this species with lengths of between 8 and 11 cm. (4 marks) Determine the 80th percentile of the lengths of this gastropod species. (3 marks) Determine the percentage of all possible samples of 25 gastropods of this species that have a mean length greater than 9.2...
The lengths of pregnancies are normally distributed with a mean of 269 days and a standard deviation of 15 days
The lengths of pregnancies are normally distributed with a mean of 269 days and a standard deviation of 15 days. a. Find the probability of a pregnancy lasting 309 days or longer. b. If the length of pregnancy is in the lowest 2%, then the baby is premature. Find the length that separates premature babies from those who are not premature. a. The probability that a pregnancy will last 309 days or longer is _______ (Round to four decimal places as...
According to one study among a certain people group, pregnancy lengths are approximately normally distributed with...
According to one study among a certain people group, pregnancy lengths are approximately normally distributed with a mean of 267 days and a standard deviation of 7 days. Approximately 12.7% of babies are premature, which means that they are born before 37 weeks in the pregnancy. A random sample of 75 pregnant women from this people group is observed and the length of each pregnancy is tracked. Let X be the number of premature babies born to these mothers. What...
The lengths of pregnancies are normally distributed with a mean of 269 days and a standard...
The lengths of pregnancies are normally distributed with a mean of 269 days and a standard deviation of 15 days. a. Find the probability of a pregnancy lasting 308 days or longer. b. If the length of pregnancy is in the lowest 4%, then the baby is premature. Find the length that separates premature babies from those who are not premature. Click to view page 1 of the table. Click to view page 2 of the table. a. The probability...
Problem 4 [6 points] When a woman learns she is pregnant, her doctor usually calculates a "due date" for the baby. The due date represents the date on which the baby will be born if her pregnancy lasts the mean length for all pregnancies. Actual lengths of pregnancy terms turn out to be nearly normally distributed about this due date (the mean) with a standard deviation of 15 days a. About what percentage of births occur within 15 days of...
not sure about this one any help would be appreciated!
The lengths of pregnancies are normally distributed with a mean of 267 days and a standard deviation of 15 days. a. Find the probability of a pregnancy lasting 309 days or longer b If the length of pregnancy is in the lowest 4%, then the baby is premature Find the length that separates premature babies from those who are not premature a. The probability that a pregnancy will last 309...
The lengths of pregnancies are normally distributed with a mean of 268 days and a standard deviation of 15 days. a. Find the probability of a pregnancy lasting 309 days or longer. b. If the length of pregnancy is in the lowest 4%, then the baby is premature. Find the length that separates premature babies from those who are not premature. Click to view page 1 of the table. Click to view page 2 of the table. a. The probability...
EQuestion Help The lengths of pregnancies are normally distributed with a mean of 267 days and a standard deviation of 15 days. a. Find the probability of a pregnancy lasting 309 days or longer b. If the length of pregnancy is in the lowest 4%, then the baby is premature. Find the length that separates premature babies tom those who are a. The probability that a pregnancy will last 309 days or longer is (Round to four decimal places as...
6.2.31 Question Help The lengths of pregnancies are normally distributed with a mean of 268 days and a standard deviation of 15 days. a. Find the probability of a pregnancy lasting 309 days or longer b. If the length of pregnancy is in the lowest 3%, then the baby is premature. Find the length that separates premature babies from those who are not premature Click to view page 1 of the table, Click to view,page 2 of the table a....
The lengths of pregnancies are normally distributed with a mean of 269 days and a standard deviation of 15 days. a. Find the probability of a pregnancy lasting 308 days or longer. b. If the length of pregnancy is in the lowest 4%, then the baby is premature. Find the length that separates premature babies from those who are not premature. Click to view page 1 of the table. Click to view page 2 of the table. a. The probability...
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