Question

Determine the support reactions and the force in member CE for the truss :

8 ft *4fty 300 lb D E F 8 ft A B 3 1000 lb 8 ft * 8 ft

Answer 1

Q » 8 ft Ye 8 1000 lb Ho 8? 8. 300 lb TRUSS BA->-40 -0.8; % (1000 lbx Cosos - 800 lb (1000 db x Sinos - 600 lb. 300 PAD PB THE Sin B²4N5 TS 2 Sing= 205 Goolb Suppork Reactions k 80026 & Fy=0 -0 → (300+Rp) - 800=0>> RF = 800-300 >> Ree soo lbs Efx=0 > 1600 - HA-H)=0 >> HF + He= 600 Emp=0 >> (HX8+300 x 12) - (800X16+ 600x8)=0; >> 8 He=(800x16 +600X8-12x300) -> H2= 1780 lbs bo Hp = 600-He = 600-1750= -1150 Hp = 1150 lost con the right direction) This; Horizontal reaction at support f acts from left to right, with magnitude of 1150 lbs. join F >HF &fp=0>> Hp-Repo RefHp = 1150 lbs: & fy=0 RE- Rep=0 = [RCF = R6= 500 lbs) Joint ci RECEBAL HE El fy=0 REF + Reesinpao. 2 RCE= - RCE SDO =-559.017 Sing zas) lbs. Hence ; force in member CE :. Rue = -559.017 lbs of the Truss = RCE= 559. 017 lbs [Compression ARE 8 PEFT Ref REF ER