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Determine the force in each member of the Gambrel roof truss shown if load P = 720 lb. (Round the final answers to their nearest whole number.) 600 lb 600 lb 300lb B 2 ft 4 in. 300 lb 8 ft S ft 8 ft S ft lb. (Compression) lb. (Tension) The force in member AB (FAB) is The force in member AC (FAc) is The force in member BC (FBc) is 0 The force in member CE (FCE) is The force in member BD (FRD) iS The force in member BE (FRE) is The force in member DF (FDF) is The force in member DE (FDE) is The force in member EF (FEF) is The force in member EG (FEG) is The force in member FG (FFG) is 0 The force in member FH (FFH) is The force in member GH (FGH) is lb. (Tension) lb. (Compression) lb. (Compression) lb. (Compression) lb. (Tension) lb. (Compression) lb. (Tension) lb. (Compression) lb. (Tension)

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Sol Fxom the diagrawn oud Loading 寸 o int A )- 3001b ンAB 513 16o AC FAC A : 1260tb a60 3 A C FAB = 1600 Ho Cc) . FAc12 to 个FGoolb 25 5 As 1600 lb + 4 5 :( 1600) = 0 24 Feb -t 20 Fee . 22000 lb- FB e t흐 (1600) -600 and (2 1320 lb (c) Fae = 1616 CC)120 25 2.5 욕 FoF Fo 1320 lb (c) 72o Foe 720-FO e-o 25 ( 132 o)-T5(-1220)- FDE 19.21b (T) Becau o Smmut FEF Be Fe, H = FAC

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