o Question 5 An aluminum nall has an excess charge of +3.2 C. How many electrons...

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Question

Answer 1

Answer #1

Excess charge on nail = +3.2 μC =3.2 x 10^-6 C

Charge on one electron = -1.6 x 10^-19 C

Thus, no of electrons that must be added = Charge on nail/ Charge on one electron=

$\frac{3.2*10^{-6}}{1.6*10^{-19}}=2*10^{13}$

So, option C is correct.

Answer 2

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