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5) Determine the point estimate of the population proportion, the margin of error for the following confidence interval, and

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Answer #1

We know that 100(1-\alpha)\% confidence interval for true proportion is given by:

\\(p-Z_{\alpha/2}\sqrt{\frac{p(1-p)}{n}},p+Z_{\alpha /2}\sqrt{\frac{p(1-p)}{n}}) \\ \\\Rightarrow p-Z_{\alpha/2}\sqrt{\frac{p(1-p)}{n}}=0.123,p+Z_{\alpha/2}\sqrt{\frac{p(1-p)}{n}}=0.547

Solving these two equations, we get,

Required point estiamte = p=0.335

Margin of error = Z_{\alpha/2}\sqrt{\frac{p(1-p)}{n}}=0.212

So, number of individual in the sample with the specified characteristic = 0.335(1000)=335

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