let
C1 = 30 micro F
C2 = 2 micro F
C3 = 10 micro F
C4 = 40 micro F
C3 and C4 are in series.
so, C34 = C3*C4/(C3 + C4)
= 10*40/(10 + 40)
= 8 micro F
the above combination is in parallel with C2.
so, C234 = C2 + C34
= 2 + 8
= 10 micro F
the above combination is in series with C1.
so, equivalent capacitance, Ceq = C1*C234/(C1 + C234)
= 30*10/(30 + 10)
= 7.50 micro F
charge on C1(30 micro F) capacitor, C1 = Ceq*V_battery
= 7.5*20
= 150 micro C (or) 1.50*10^-4 C <<<<<<<<------------Answer
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