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[1 b + 1 Given the matrix A The value of b such | 3 8 that the det(A) = -1 is 2 Thus the matrix A is called identity identity
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all AS btl 8 3 TA = 8-16+1) 3 = -1 8-36-3 = -1 5-3b = -1 b=1 / 2 = ? 1 3 Az [ 3 8 we know that A is symmetric If ASAT Now her

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