Problem 4 FI 30° 30° L А L t L F2 F1= 3.4 KN F2= 6.5 kN L= 1.0 m The beam's support at A is a fixed support. The weight of the beam is neglected. Calculate the support reactions at A. Answer:
Fi 60 135 60° 609/ 30 (4 m, 4m,-2m) If F1- 8.26 KN, F2 3B4 KN, and F3 12.2 KN, determine the magnitude and direction of F required for equilibrium. F1 is rotated 30 degrees in the x-y plane and 60 degrees up in the z direction. Alpha, Beta, and gamma for F2 are 135, 60 and 60 degrees, respectively. F3 passes through the origin and another point (4,4,-2).
A foundation mat supports the four columns shown. Given that: F1 - 14 kN, F2 - 12 kN, F3-25 kN, distance x 7 m, and distancez-4 m. F3 F1 F2 5 m Select the closest choice to your solution and ONLY TYPE THE LETTER IN THE BLANK (A, B, C, D). Select the closest choice to your solution and ONLY TYPE THE LETTER IN THE BLANK (A, B, C, D). (Q1) The equation that most represents the moment around x-axis...
Statics problems
Question A2 The plane truss shown in Figure A2 is supported at points A and J. -30° and the external loads are Fi 1.5 kN and F 3 kN. Draw the free body diagram of the truss. Determine all the reactions at the supports or, if this is not possible, explain why. a) Calculate the internal forces in members CF, EH, GH and HI, stating whether they are in tension or compression. b) (12) Are members CF and...
Problem 1.9 The beam supports the distributed load with Wmax 3.2 kN/m as shown. The reactions at the supports A and B are vertical. .5 m .5 m PartA Determine the resultant internal loadings acting on the cross section at point D Express your answers, separated by commas, to three significant figures. kN, kN, kN.m Submit Request Answer
Problem 10. If two forces are acting on a beam as shown, and FI -10 N, and F2 - 15 N, what is the force of F3n if the beam is not to move? Problem 11. Four people are pushing on a door as shown on the figure, and the forces given are; FI - 10 N, F3 - 15 N, F4 is 35 N, what is the force of F2 if the door is not moving? Problem 12. If...
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Problem 2-7 (page 29). Resolve the force Fi into components acting along the u and v axes and determine the magnitudes of the components. 1. 30° 75° F1 = 4 kN 30°
The beam shown in Figure 1 has a clear span length of L = 7.6 m and x : 1.5 m. The beam cross section is shown in Figure 2 and supports the following loads: WL = 30 kN/m. Wb = 50 kN/m, Q.-50 kN, QD = 80 kN, and supports its own weight. Assume f,'-25 MPa,.-420 MPa, b-350 mm. d-702 mm, h 750 mm, colinn width-450 1. Calculate the beam own weight 2. Calculate the ultimate loads applied on...
(5%) Problem 2: Ahorizontal force, Fi = 75 N, and a force, F2 = 19.9 N acting at an angle of 0 to the horizontal, are applied to a block of mass m =3.9 kg. The coefficient of kinetic friction between the block and the surface is u = 0.2.The block is moving to the right F. Randomized Variables F F1 75 N F2 = 19.9 N m 3.9 kg Otheexpertta.com 50% Part (a) Solve mumerically for the magnitude of...
Question 5.6-7
uut be used in od is axis bending (i.e., it must bend about the 2-2 (or y) axis of the cross section). weak (a) Ift 5.6-7 A simple beam A figure (a) Calculate the required section modulus S if (b) R th 5.6-9 Onllow = 124 MPa, L = 9.75 m, P-13 kN, and wooo q = 6.6 kN/m. Then select a suitable I-beam (IPN shape) from Table F-2, Appendix F, and tert recalculate S taking into account...