Question

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U Problem 1 Two gliders of different mass move toward each other on a frictionless air track (see the figure below). The mass of glider A is 0.50 kg, while the mass of glider Bis 0.30 kg. Their velocities before the collision are shown in the figure below. The collision between the two gliders is elastic. Questions 1 and 2 beldw refer to this problem. The positive reference direction is to the right VALE = 2.0 m/s UB1x = -2.0 m/s X А B mA = 0.50 kg MB 0.30 kg

Answer 1

Answers from Momentum conservation MACALL + me Biz -) m Unax +mBuBax 0.S0 XQ + (0.30) (2) 0.5 UAga t 0.30 UBIX 1-0.6=0.JUAgxt 0.30 UBOX 0.4 = 0.5 UA2x + 0.3 UBIX € T

as motion & clastic, e=1 coefficient of restitution es Uban - Vaga AIR - UBIX e=1 Ubax - Maga then UB2x = 4+ UAR [put in UBax-box 2-(-2) then 4= 0.42 0.5 base +003 (ut haga ) 0.4 - 1.2 = 0.SUAga Kenax= -lm/o Speed of a 0.8 also, UBg2 = 4-1 = 3 m/ speed of B.
use momentum conservation and also given motion is elastic then coefficient of restitution will be 1.