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Problem 14: Quadratures Given the integral: Ś (2.5 - 2 ) da Using the results from...
Problem 13: Quadratures Given the integral: & (2.5 – 2 ) da Using the results from...
Problem 13: Quadratures Given the integral: & (2.5 – 2 ) da Using the results from the last two computations, the error in the single trapezoid, T., value for the integral is estimated as e1-0.25 None of the above. e1-0.44 e1-1.95 e1-1.25
Problem 12: Quadratures Given the integral: Ś (2.5 – 2 ) dz Using a compound trapezoid...
Problem 12: Quadratures Given the integral: Ś (2.5 – 2 ) dz Using a compound trapezoid rule with two trapezoids, T2, the integral is estimated as T2-5.40 T2-5.59 None of the above. T2-5.67 T2-5.25
Problem 11: Quadratures Given the integral: S (2.5 – 2 ) da Using a single trapezoid...
Problem 11: Quadratures Given the integral: S (2.5 – 2 ) da Using a single trapezoid rule, T1, the integral is estimated as 525 None of the above. T1=540 T1559 T1567
Problem 15: Quadratures Given the integral: & (2.5 – 2 ) da Applying Gauss Quadrature on...
Problem 15: Quadratures Given the integral: & (2.5 – 2 ) da Applying Gauss Quadrature on the integral, the required mapping (1) where 5 € (-1, +1] is () = 7.005 +3.00 (C) = 1.506 +3.50 (C) = -7.005 +3.50 (C) = 5.005 +2.00 None of the above.
Problem 16: Quadratures Given the integral: À (2.5 – 2 ) dz The Jacobian of the...
Problem 16: Quadratures Given the integral: À (2.5 – 2 ) dz The Jacobian of the mapping required to evaluate the integral is J-3.50 None of the above. J-5.00 J-1.5 J-7.00
D Question 17 1 pts Using a two-point Gauss quadrature, where the weights and abscissae are...
D Question 17 1 pts Using a two-point Gauss quadrature, where the weights and abscissae are provided in the table 10 1 1.0 2 1.0 the value of the integral is estimated to be 5.69 None of the above. 5.54 5.67 5.78 Question 16 1 pts Problem 16: Quadratures Given the integral: (2.5 - 3) de The Jacobian of the mapping required to evaluate the integralis J-3.50 None of the above. J-5.00 J-1.5 J-7.00
Problem 6 Using Stokes' Theorem, we equate F dr curl F dA. Find curl F- PreviousS...
Problem 6 Using Stokes' Theorem, we equate F dr curl F dA. Find curl F- PreviousS us Problem ListNext Noting that the surface is given by (1 point) Calculate the circulation, Fdr7in z - 16-x2 - y2, find two ways, directly and using Stokes' Theorem. dA The vector field F = 6y1-6y and C is the boundary of S, the part of the surface dy dx With R giving the region in the xy-plane enclosed by the surface, this gives...
2. Flux calculations: Set up the double integral for Js F dA using cylindrical, spherical or shad...
2. Flux calculations: Set up the double integral for Js F dA using cylindrical, spherical or shadow method as appropriate. (a) Sis defined by z2 +--4for-1SS3,oriented away from y-axis. F-3 (b) Sis given by z2 + y2 + z2-9and F-1n+zk. (c) S is the conical face -V+ over the region r S 2 on the zy-plane, oriented downwards.
2. Flux calculations: Set up the double integral for Js F dA using cylindrical, spherical or shadow method as appropriate. (a) Sis...
2 Problem 3 (25 points) Let I = ïrdz. a) [by hand] Use a composite trapezoidal rule to evaluate 1 using N = 3 subintervals. b) MATLAB] Use a composite trapezoidal rule to evaluate I using N - 6 subin...
2 Problem 3 (25 points) Let I = ïrdz. a) [by hand] Use a composite trapezoidal rule to evaluate 1 using N = 3 subintervals. b) MATLAB] Use a composite trapezoidal rule to evaluate I using N - 6 subinterval:s c) by hand] Use Romberg extrapolation to combine your results from a) and b) and obtain an improved approximation (you may want to compare with a numerical approximation of the exact value of the integral
2 Problem 3 (25 points)...
Problem 2 You are going to find a definite integral of a function by using the 'changevar maple f...
Maple Lab- plz do both on Maple, as soon as possible,
thanks in advance
Problem 2 You are going to find a definite integral of a function by using the 'changevar maple from "student" package a) First command in you are going to integrate each function over the given interval by using 'u-substitution ou are going to integrate each function over the given interval directly using the 'int' to verify your results above. 1)f:-: 2 (1 +2x)4 Interval (1,2) 2)...
Problem 13: Quadratures Given the integral: & (2.5 – 2 ) da Using the results from the last two computations, the error in the single trapezoid, T., value for the integral is estimated as e1-0.25 None of the above. e1-0.44 e1-1.95 e1-1.25
Problem 12: Quadratures Given the integral: Ś (2.5 – 2 ) dz Using a compound trapezoid rule with two trapezoids, T2, the integral is estimated as T2-5.40 T2-5.59 None of the above. T2-5.67 T2-5.25
Problem 11: Quadratures Given the integral: S (2.5 – 2 ) da Using a single trapezoid rule, T1, the integral is estimated as 525 None of the above. T1=540 T1559 T1567
Problem 15: Quadratures Given the integral: & (2.5 – 2 ) da Applying Gauss Quadrature on the integral, the required mapping (1) where 5 € (-1, +1] is () = 7.005 +3.00 (C) = 1.506 +3.50 (C) = -7.005 +3.50 (C) = 5.005 +2.00 None of the above.
Problem 16: Quadratures Given the integral: À (2.5 – 2 ) dz The Jacobian of the mapping required to evaluate the integral is J-3.50 None of the above. J-5.00 J-1.5 J-7.00
D Question 17 1 pts Using a two-point Gauss quadrature, where the weights and abscissae are provided in the table 10 1 1.0 2 1.0 the value of the integral is estimated to be 5.69 None of the above. 5.54 5.67 5.78 Question 16 1 pts Problem 16: Quadratures Given the integral: (2.5 - 3) de The Jacobian of the mapping required to evaluate the integralis J-3.50 None of the above. J-5.00 J-1.5 J-7.00
Problem 6 Using Stokes' Theorem, we equate F dr curl F dA. Find curl F- PreviousS us Problem ListNext Noting that the surface is given by (1 point) Calculate the circulation, Fdr7in z - 16-x2 - y2, find two ways, directly and using Stokes' Theorem. dA The vector field F = 6y1-6y and C is the boundary of S, the part of the surface dy dx With R giving the region in the xy-plane enclosed by the surface, this gives...
2. Flux calculations: Set up the double integral for Js F dA using cylindrical, spherical or shadow method as appropriate. (a) Sis defined by z2 +--4for-1SS3,oriented away from y-axis. F-3 (b) Sis given by z2 + y2 + z2-9and F-1n+zk. (c) S is the conical face -V+ over the region r S 2 on the zy-plane, oriented downwards.
2. Flux calculations: Set up the double integral for Js F dA using cylindrical, spherical or shadow method as appropriate. (a) Sis...
2 Problem 3 (25 points) Let I = ïrdz. a) [by hand] Use a composite trapezoidal rule to evaluate 1 using N = 3 subintervals. b) MATLAB] Use a composite trapezoidal rule to evaluate I using N - 6 subinterval:s c) by hand] Use Romberg extrapolation to combine your results from a) and b) and obtain an improved approximation (you may want to compare with a numerical approximation of the exact value of the integral
2 Problem 3 (25 points)...
Maple Lab- plz do both on Maple, as soon as possible,
thanks in advance
Problem 2 You are going to find a definite integral of a function by using the 'changevar maple from "student" package a) First command in you are going to integrate each function over the given interval by using 'u-substitution ou are going to integrate each function over the given interval directly using the 'int' to verify your results above. 1)f:-: 2 (1 +2x)4 Interval (1,2) 2)...
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