Question

two part question!

Bolve the equation for exact solutions over the interval [0, 2x). sinºx + 2 sin x + 1 = 0 Select the correct choice below and if necessary, fill in the answer box to complete your choice O A. The solution set is (Type an exact answer, using x as needed. Type your answer in radians. Use integers or tractions for any numbers in the expression. Use a comma to separate answw OB. The solution is the empty set.

Answer 1

Solution given that, equation is sinane + 2 sinx + 1 = 0 we will solve this algebrically, sin2x + 2sinx + 1 = 0 sinze + sinnt sina + 1 = 0 sinu (sins +1 + 1(sins +1) (sinne +1) I sinx + 1) = 0 I sinx + 1)2 = sinn +1 = sinn =) sint (-1) 0 O x = 3T + 2 TO 2 31+ For any Integer in Interval [0, 25) put no N = 3T 2 + 2010) solution, set M= 37 >> given that COSME 1 2 is { } uonth ziau So, LOS 24 = 1 22= cost (1)

we If use given Information, that means, + 2TN, 뜰 For any Integarn 20 = 20M RE + TM, STT + TM 6 6 ) = In Interval [0, 257) put, n=0 * + ), +o) 풍, A= 5T 6 Now, Put m2 , A= T + ㅠ , = 77 10 G , { , , , Solution set , HE

Answer 2

[REMOVED]