Since the image is going to be 3x the size of the original, we know that it must be a virtual image.
Also since the image is going to be 3x larger, the image must also be 3x farther away than the object (it's a concave mirror).
If s is the object distance and s' is the image distance, we know that s'=-3s.
*Note that s' is negative: this is because the image must be upright, which means m must be positive in the equation for magnification m=-s'/s*
Since focal length (f) is given by f=2/R, and the miror equation states that (1/s)+(1/s')=1/f, we can substitute in for f and get:
(1/s)+(1/s')=(2/R)
Also, since we found that s'=-3s, we can further substitute to get:
(1/3s)+(1/s)=(2/R)
Simplifying, we get that (2/3s)=(2/R)
Plug in 50cm for R, and you get that s=16.6666666666
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