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Mystery Problem 5. The uniform plate 26X28 shown weighs 200N and is supported in a horizontal position by a hinge at A at the

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At hinge A (1) + Azka - Ax A + Ay j + k ..(2) = MA MZ Max i toj Hinge. M40 TBC TBC UBC A -24 TBC - 12 + 2ok 544 Eq. (3) w - 29. 4324 TBC - 22.2948 TBej 21.0943 TBC K & 506595 Tibet Eq. (B) 8 Alexw Moment e I due to W = 14 1XF 200 k) soj Nem + 2800 EqNow, Support Reactions Apply force equilibrium for Eq. (1), (3) and (4) E Fx iei sn=0 - О Axe 12 TBC √544 Ax + 64.6154 N Ans.Az = 92.3076 N Ans. Also, ŽMZ @A Lk = O for For A, B & C MAZ 21.0943 TBC MAZ 2649.2289 sem Ans.

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