Sol::
Given:
Radius of smaller loop(Rs)= 2.6 cm
Current in smaller loop(Is)= 12 A
Current in bigger loop(Ib)=20 A
uo=1.26*10^-6 T.m/A
The magnetic field at the center of a circular loop of radius "r" and current "i" is;
B = ui/2r
The field is along the axis , one way for counterclockwise current and the other direction for clockwise current.
So, let us assume the current in the large loop is in the opposite direction and the set its field equal to the field of the small loop;
u(Ib)/2Rb = u(Is)/2*Rs
Rb = Rs*Ib/Is
= (2.6)(20)/(12)
= 4.33 cm
≈ 0.0433 m
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