Question

Two concentric current loops lie in the same plane. The smaller loop has a radius of 26 cm and a current of 12 A. The bigger
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Answer #1

Sol::
Given:

Radius of smaller loop(Rs)= 2.6 cm
Current in smaller loop(Is)= 12 A
Current in bigger loop(Ib)=20 A
uo=1.26*10^-6 T.m/A

The magnetic field at the center of a circular loop of radius "r" and current "i" is;

B = ui/2r

The field is along the axis , one way for counterclockwise current and the other direction for clockwise current.

So, let us assume the current in the large loop is in the opposite direction and the set its field equal to the field of the small loop;

u(Ib)/2Rb = u(Is)/2*Rs

Rb = Rs*Ib/Is

= (2.6)(20)/(12)
= 4.33 cm
≈ 0.0433 m

Hope this answer helps you
Hope will get the VOTE
Thank you

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