Question

A small circular loop of area 6.00 cm is placed in the plane of, and concentric with, a large circular loop of radius 1.00 m. The current in the large loop is changed at a constant rate from 200 A to -200 A (a change in direction) in a time of 1.0 s, starting at t = 0. What is the magnetic field B at the center of the small loop due to the current in the large loop at t = 0? Take B as positive if out of the paper. found between Tries 0/10 Tries Submit Answer Incompatible units. No conversion found between Tier "V" and the required units. ? 1 Previous What is the magnetic field B at the center of the small loop due to the current in the large loop at t = 0.50 s? Take B as positive if out of the paper. Submit Answer Unable to interpret units. Computer reads units Tries 0/10 Previous Tries 0/10 Tries as. What is the magnetic field B at the center of the small loop due to the current in the large loop at t = 1.00 s? Take B as positive if out of the paper. Submit Answer Tries 0/10 What emf is induced in the small loop at t = 0.50 s? Take emf as positive if counterclockwise. Note that since the inner loop is small, you can assume that the B field due to the outer loop is uniform over the area of the smaller loop. Submit Answer Tries 0/10

Answer 1

222222222 rea of small looh - 6 x 10-4 m Radius of langer doroh = tm. At eto I - 2004 Magnetic field at the centre loh = to I 2R = 4TX 107 x 200 of = 45810-5 = 483. 14X10-5 - 12.56*10-5 = 1.258 810-4T (out of plane of paper) At =055 -0 • 8:0 ho t= 15 1 - 200 A B = HI U 4. = 411810-** (-200) 2x1 = -1.256 X10 AT { into the plane of paper) &=- A6 By Leryn law, ent must be such that il opposes the change in flux =-(0-% linked to it. As flur decrease in (tj. ti) out of place of paper deriction ent must be anticlockwise to oppose the - (0-1253X104) decrease (050) 2672x/0-4