13. Find the critical values of the function, f(x) = 2x - 3x - 36x +...
Find all the critical numbers of the function. f(x) = 2x2 + 3x? - 36x + 10 O A. -2 OB. 6 O C. -3,2 OD. 3, -2
Given f(x) = 2x - 3x - 36x +6. (a) Find the intervals on which fis increasing or decreasing. (b) Find the relative maxima and relative minima of f. Select one: a. (a) Increasing on (-3,2), decreasing on (-0, -3) and (2,00) (b) Rel. max. f(2)= 62 rel. min. f(-3) = -33 o b. None of these c. (a) Increasing on (-2, 3), decreasing on (-00,-2) and (3,0) (b) Rel. max. f(3) = 75, rel. min. f(-2) = -50 d....
Consider the function f(x) = x3 + 3x² - 9x +1. (a) Identify all critical points of f(x). (Providing the -values will be sufficient. Hint: They will be integers.) (b) Use your answer from (a) to identify the absolute maximum value (global max) and absolute minimum value (global min) of f(x) over the x-interval (-2,2]. (Be clear and correct about what you are checking for full credit!)
1. (12) Find the critical points and the extreme max and min values of the function f(x) = 3x* - 4x on the interval [-2, 2].
1. (12) Find the critical points and the extreme max and min values of the function f(x)= 3x* - 4x' on the interval [-2, 2].
(1 point) Consider the function f(x) = -22% + 36x? - 162x + 10. This function has two critical numbers A <B: А 3 and B 9 f"(A) 36 f"(B) = -36 Thus f(x) has a local -206 and a local 10 at A (type in MAX or MIN) at B (type in MAX or MIN).
. Find the absolute max and min values of f(x) in the given interval: f(x) = x^2- 2x + 5 over the closed interval [-1,2]
+ 1) Find all relative extrema for y = _ 13 x3 + 3x + 4 2) Find all absolute extrema of f(x) = 2x3 - 9x2 + 12x over the closed interval [ -3,3). Given: f(x) = 2x3 – 3x2 – 36x + 17 3) Find all critical values for f(x). 4) Find all relative extrema of f(x). 5) Find all points of inflection of f(x).
Find any values of cwhere the function f(0) = 2x² + 3x – 4satisfies the conclusion of the Mean Value Theorem on the interval (0,3).
The sum of the absolute maximum and absolute minimum values of the function g(x)=-2x^3+3x^2 on the interval [0,2] is: a)-4 b)-3 c)0 d)1