Question

The figure shows a transmission shaft. The steel solid shaft is 200 mm long between self-aligning bearings at A and B. Belt f
A. Load Analysis Fc = 10 Points FC A1. FBD C AB M = 0; 100 mm 100 mm R VRE VIN) A2. SED V= Vc M (N.inm) Vs A3. BMD MA MC = T(
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Answer #1

The torque acting on the shaft is calculated. This calculated torque will be the torsional moment on the shaft. The free body diagram on the horizontal plane is prepared. The reaction forces at the fixed ends are calculated. The shear force diagram is prepared after that. Once the shear force diagram is obtained, the Bending moment diagram is then prepared.

The bending stress is calculated for the maximum bending moment. Similarly torsional shear stress is then computed for the given torsional moment or the torque. The stresses acting on the elements are then shown.

For the calculated stresses or the bending or the torsional moment, the principal stresses can then be computed. The maximum torsional shear stress can also be computed.

For a factor of safety of 2, assuming the material to be AISI1040, the safe diameter is then calculated.

Note: The diameter of the shaft was not clear in the image, so all the stress calculations are done assuming it to be 30mm.

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