ANSWER :
2. Determine ly and ky. Hint: Section 1 is the left triangle. Section 2 is the...
2. Determine ly and ky. Hint: Section 1 is the left triangle. Section 2 is the right rectangle. Section 3 is the semicircle and section 4 is the empty circle. (20 pts) 4 mm mm 4mm 8 mm -12mm 16 mm
2. Determine ly and ky. Hint: Section 1 is the left triangle. Section 2 is the right rectangle. Section 3 is the semicircle and section 4 is the empty circle. (20 pts) у 4 mm mm 4 mm 1 8 mm X -12mm- 16 mm
Problem # 1 Determine ly and ly for the section given below 120 mm 400 mmm 400 mm 120 mm -120 mm 640 mm
Question 2 1 pts A charge of +8 micro-coulombs is placed at the bottom left corner of a rectangle, a charge of -8 micro-coulombs is placed at the top left corner of a rectangle, a charge of +8 micro-coulombs is placed at the bottom right corner of a rectangle, and a charge of +8 micro-coulombs is placed at the top right corner of a rectangle. The rectangle has a height of 22.9 cm and a width of 14.5 cm. (See...
Question 1 1 pts A charge of +4 micro-coulombs is placed at the bottom left corner of a rectangle, a charge of -4 micro-coulombs is placed at the top left corner of a rectangle, a charge of +8 micro-coulombs is placed at the bottom right corner of a rectangle, and a charge of +8 micro-coulombs is placed at the top right corner of a rectangle. The rectangle has a height of 6.5 cm and a width of 15.9 cm. (See...
Write a Java application to find the area of 1) rectangle 2) Triangle 3) Circle using runtime polymorphism concept. Shape Area rectangle length*width Triangle 0.5*length*width Circle PI*radius*radius. I am confused as to what polymorphism is and would really appreciate some help. This is in Java as well.
Problem 7.29 Determine the coordinates of the centroids. Solution: Break into a rectangle, a triangle and a circular hole TE 5[(10)(8)] + 12 (_(8X6)) - 4[*(291 = 6.97 in (10)(8) + (8)(6) - (2) 4[(10)(8)] + 48 (4 (8)(6)) - 3[(2)*1 = 3.79 in (10)(8) + (86) - (2) 2 in 8 in o 16.97 in y = 3.79 in 3 in -6 in 10 in
Problem 3 (20 Pts] 1. Reduce the loading shown to an equivalent system formed by two parallel forces applied at I and F. x 2. Determine the support reactions. 0.9 kips slip Skin 0.9 kip -4 --12 -14 - 14- . 15.95 - 315 REF Leif x= kxd Ly < Fy = Ky + Ly -0.9-1- -0.9 = 0 E fy=Ly + ky = 5.4ku 31.5 ft C4 1 'ft
6. (23 pts.) Given: cos(°/2) = -1/4 and "/2</2<311/4. Form a right triangle with the given information. Determine the following and report all numerical answers in exact form. Report angles to two decimal places. a. (02 pts.) The missing side b. (03 pts.) sin(°/2 c. (03 pts.) tancº/2) d. (02 pts.) sin() e. (02 pts.) cos() f. (02 pts.) tan() g. (02 pts.) sin(20) h. (02 pts.) cos(2p) i. (02 pts.) tan(2) 1. (01 pts.) The angle/2 k. (01 pt.)...
as shown in Fig.2. The lengths of two 2. Three bars form an isosceles right triangle, right angle sides are L, which is 1000 mm. The cross section area of the three bars are 1000 mm2. Young's modulus of bars are E-21x10 N/ mnt Please find the global stiffness matrix of these bar element system. If the numbering of the bar nodes changes, does the global stiffness matrix change? (15 %) y 1 (3) (1) (2) 3 2 Fig.2 Bar...