Question

Problem 3 (20 Pts] 1. Reduce the loading shown to an equivalent system formed by two parallel forces applied at I and F. x 2. Determine the support reactions. 0.9 kips slip Skin 0.9 kip -4 --12 -14 - 14- . 15.95 - 315 REF Leif x= kxd Ly < Fy = Ky + Ly -0.9-1- -0.9 = 0 E fy=Ly + ky = 5.4ku 31.5 ft C4 1 'ft

Answer 1

FBD ogkies 914ps 1.94IPS 9.8KIPS 12ft 14ft Tuft loft {fx=0 kx=La ac Efy=0 0.9 +1.8+1.8+0.9 kytly = 5.4 kips Take moment about k take Clockwise moment the & ? Anticlocknise moment - ve 0.98 16+ 1.8x28+1.8x42 to.9656 11.925kips ky + 11.925 – 5th Ky -5.6 -11.925 Ky=-6525 kips Ky and by an acts in opposite Equilibrium. direction Reactions. to be in