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Question #5 A-D. Please show work!

5. The quality control department of a company has decided to select a sample of items from each shipment of goods it receive
4 6 3 4 4 6 3 5 1 6 2 4 7 1 5 2 6 1 3 1 2 4 2 3 2 2 2 3 3 3 Suppose the company does not know the proportion of defective ite
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Answer #1

of P is Meam proportiom P = 550 = 0.016. 2 The estimate for the proportion defective items P = 0.016 ho 16 Using 3r limit the

P- 3PC-P m -0. 0527 be in negative Since proportiom com not be the lower Control limit LCL = 0

The central limit for the proportion of defective items rehe obinet le 07.016 mem mortal (d) the upper contred limit for the

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