P(A = 1) = 1/4, P(A = 0) = 3/4
P(B = 1 | A = 1) = 1
P(B = 0 | A = 1) = 0
P(B = 1 | A = 0) = 1/2
P(B = 1 | A = 0) = 1/2
(d) P(B = 1 | A = 0) = 1/2 = 0.5
(e) P(A = 0, B = 1) = P(B = 1 | A = 0)*P(A = 0)
= 1/2*3/4 = 3/8 = 0.375
(f) P(A = 1, B = 1) = P(B = 1 | A = 1)*P(A = 1)
= 1*1/4 = 1/4 = 0.25
(g) P(B = 1) = P(A = 0, B = 1) + P(A = 1, B = 1) = 5/8 = 0.625
(h) P(A = 1 | B = 1) = P(A = 1, B = 1)/P(B = 1)
= (1/4)/(5/8)
= 0.4
Question 3: A new virus has been circulating in Townsville. Fortu- nately, a pharmaceutical company called...
Question 3: A new virus has been circulating in Townsville. Fortu- nately, a pharmaceutical company called Umbrella Inc. has developed a test for diagnosing - before symptoms appear - individuals who are infected so that they can be preemptively quarantined. The probability an individual is currently infected is . Therefore, the prob- ability he/she is not infected is. If an individual is infected, Umbrella Inc.'s test always reports "VIRUS DETECTED" (i.c. with probability 1), but if an individual is not...
Question 3: A new virus has been circulating in Townsville. Fortu- nately, a pharmaceutical company called Umbrella Inc. has developed a test for diagnosing - before symptoms appear – individuals who are infected so that they can be preemptively quarantined. The probability an individual is currently infected is . Therefore, the prob- ability he/she is not infected is . If an individual is infected, Umbrella Inc.'s test always reports “VIRUS DETECTED” (i.e. with probability 1), but if an individual is...
2 pts 1 Details < > Question 16 A certain virus infects one in every 300 people. A test used to detect the virus in a person is positive 80% of the time if the person has the virus and 8% of the time if the person does not have the virus. (This 8% result is called a false positive.) Let A be the event the person is infected" and B be the event "the person tests positive". a) Find...
hi, my answers seemed strange after using Bayes theorem, so I am
unsure if I made the right calculations. Please show your work so I
can catch my error :)
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A civil engineer has been studying the frequency of vehicle accidents on a certain stretch of interstate highway. Longterm history indicates that there has been an average of 1.70 accidents per day on this section of the interstate. Let r be a random variable that represents number of accidents per day. Let O represent the number of observed accidents per day based on local highway patrol reports. A random sample of 90 days gave the following information. r 0 1...
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