Question

This is my physics lab using the Phet "Geometric Optics" stimulation. Could I please get help with steps 8-10.

0.8 1.53 1.3 No Rays Marginal rays Principal rays Many rays 2nd Point Change Object Show Guides Virtual Image Screen ✓ Ruler curvature radius(m) refractive index diameter(m) ES 40 -SE 100 120 140 160 Step 2: di- the distance between the image and the lens di = 200 cm Drag the ruler to the left and measure the distance between the bottom edge of the arrow (that is touching the principal axis) and the lens. This is the object distance. do - the distance between the object and the lens do = 116 cm Focus

Answer 1

Step 8:

Using the ruler to measure 320 cm

First, measure the distance for 200 cm and place the object as shown below:

By convention, the object is put on the left-hand side.

Now we know that 320 cm - 200 cm = 120 cm

So, we move ONLY THE RULER by 120 cm more towards left of the object as shown below:

Now, ONLY MOVE THE OBJECT to the Zero of the ruler as shown below:

Now, our object is 320 cm away from the lens.

Image distance is 100 cm

Prediction was = 98.762 cm

My prediction was very close, with just the difference = 100 - 98.762 = 1.238 cm

Image is real as we are able to get it on the screen.

Yes, my prediction was correct.

The image is inverted and smaller than the object. Yes my both the predictions were correct.

Step 9: Focal length , f = 75.471 cm

d_o = ⅔ f = ⅔ x 75.471 cm = 50.314 cm ≈ 50.3 cm

1/d_o + 1/d_i = 1/f

1/50.314 + 1/d_i = 1/75.471

d_i = - 150.942 cm

d_i is negative

Image will be virtual as d_i is negative.

M = - d_i/d_o

M = 3.0008

Image will be upright

Step 10:No i do not see an image

Light rays diverge after passing through the lens

Yes, I see the Image now

d_i experiment = 184 cm

The prediction was slightly different than the experimental value.

my image is virtual and erect Also larger than my object. my all predictions were correct

If it helps, kindly upvote. Comment below for doubt.