Question

Given g(x) = log 5(x + 4). What is the vertical asymptote? Determine the given function's domain and range. What is the vertical asymptote of g(x)? X What is the domain of g(x) = log 5(x + 4)? ho (Simplify your answer. Type your answer in interval notation) What is the range of g(x) = log 5(x + 4)? (Simplify your answer. Type your answer in interval notation)

Answer 1

s(x) = logs (x+4) Vertical Asymptore OP Possible paints where function does't defined Here logo is not defined so when (x+4) equal Function is does't exist x+4 -0 x = -4 Hence Vertical Asymptote e = - 4 Domain: For defining function - x + 4 e > -4 interval Range: - lim logg (x+4) lim xt -0 logs(x + 4) = -00 Range: [ 1-00,00)

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Answer 2

SOLUTION :

g(x) = log5 (x + 4) 

(4 + x)  > - 4 

At x = - 4, g(x) = log5 (0) = - ∞ 

a.

Vertical asymptote is at x = -4, where g(x) is  - ∞ . (ANSWER).

b.

Domain is : x > - 4  I.e. ( - 4, ∞)  (ANSWER)

c. 

Range is (- ∞, ∞) (ANSWER)