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1) Figure 1 shows a typical duct layout. Design the duct system using equal friction method. Take the velocity of air in the

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+ 3 m/s A m B 6m Fan D m 2m C 4m . 1m/s. For Section AB * volume flow rate (Qi) 4 + 3+1 = 8 m/s. velocity in moun durt 8 mls.Foo seckon BD Since we or using an using eaver friction method farction rate remans same for all Sechon ДР. 0.00 0.367 (Birhefor section of 1.352 APA 0.0022,63(Qw) 0.0 586 mm Holm D4.93 (Qu)orga imo/s. 0.5200m A. 1/40R: 44 (0.52) 0.2123 me velocitySeekon DE 3 mls. 1.853 Qv= - 0.00 2.267 0.05 86 = 0.913. 03 0.782.8 m Asca= A= 914601): 0.48)3 m2 velocity (C)- 3 0.4313 6.23Dynare possua doop. fitting (Acto Bo) = 0.25( 35-45- 24.027) - 2.15 pa Asting (Boto DFG) = 0.25 (27.027 - 13.312) 3.420 Pa elbox is just collective answers of the each section and some given data in problem..

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