Question

A source of polarized light has a wavelength of 680 nm (680x10-9m), an intensity of 3.2 W/m², and is polarized at 17 degrees clockwise from the 12 o'clock vertical position. This source of polarized light passes through a polarized lens oriented at 50 degrees clockwise from the 12 o'clock vertical position. a) What is the intensity of the light after passing through the polarized lens? b) What is the frequency of the light?

Answer 1

Solution:

A source of polarised light is polarised at 17 degree clockwise from 12 o'Clock vertical position.

Intensity of source polarised light is Io = 3.2 W/m^2

Now, This source polarised light passes through a polarised lens at 50 degree clockwise from the 12 o'clock vertical Position.

From Malus Law,

Intensity of light after passing through the polarised lens is I1=Io*[cos^2$\Theta$]

Where, Io = Intensity of light which is polarised at 17 degree clockwise from 12 o'clock vertical position.

And, $\Theta$ = 50 degree.

Therefore, Intensity = (3.2) * [Cos50]^2 = 1.32 W/m^2

We Know frequency of light, f = C / $\lambda$ = (3*10^8) / (680*10^-9) = 4.41176*10^14 Hz

a) Intensity of Light after passing through lens is 1.32 W/m^2

b) Frequency Of Light is 4.41176*10^14 Hz