Question

le Home Insert Draw Page Layout Formulas. Data Review View X Calibri 11 ν Α Α' a Wrap Text aste BIU V a. Av Merge & Center Clipboard Font Alignment 22 ✓ fx D E F G H 2. الا 10 N А B с 162 202 157 158 264 263 4 200 203 5 201 203 6 230 235 7 203 230 8 153 154 9 152 154 10 154 154 11 Cholesterol Cholesterol at 46 12 13 14 9df 15 0.937031 Correlation R 16 0.101686 sig.(2-tailed) 17 1.82258 + 18 2.262157 tablet 19 20 21 22 23 24 25 26 27 2B 29 30 31 32 Sheet1 Type here to search o i

Answer 1

Exercise 1 -

Correlation coefficient is 0.937031 which shows there's strong correlation.

Exercise 2 -

Correlation coefficient is positive.

Exercise 3 -

It means that there is positive relationship between two variables i.e. As value of x-variable ariable increases, there will be increase in y-variable also.

Exercise 4 -

Hypothesis -

Null hypothesis - H₀ - there is no significant correlation between two variables. I.e. $\rho$ = 0.

Alternative hypothesis - H₁ - there is significant correlation between two variables.

Exercise 5 -

If p-value is less than $\alpha$ , then we have to reject H₀.

Since, p-value = 0.10 > 0.05

So, we do not reject H₀ at 5% level of significance.

Exercise 6 -

If calculated t value is greater than or equal to tabulated value of t, then we have to reject H₀ at 5% level of significance.

Here, t = 1.82258

Table value t = 2.262157

Since, calculated value of t is less than tabulated value, so we do not reject H₀ at 5% level of significance.