just need the diagram. thanks Problem 13 A converging lens with a focal length of 12...
A converging lens with a focal length of 12 cm produces a 3-cm high virtual image of a 1-cm high object. Which entry in the table below is correct? Draw a neat ray diagram. PLEASE REMEMBER TO DRAW THE RAY DIAGRAM. Problem 13 A converging lens with a focal length of 12 cm produces a 3-cm high virtual image of a 1-cm high object. Which entry in the table below is correct? image distance location of image A) 8 cm...
A converging lens with a focal length of 12 cm produces a 3-cm high virtual image of a 1-cm high object. Which entry in the table below is correct? image distance location of image A) 8 cm same side of lens as object B) 8 cm opposite side of lens from object C) 12 cm opposite side of lens from object D) 24 cm opposite side of lens from object E) 24 cm same side of lens as object (Draw...
A converging lens with a focal length of 12.0cm forms a virtual image 8.00mm tall. Image is 17.0cm from the lens. Calculate (a)the position of the object, (b)magnification of the lens, (c)height of the object. (d)Is the image upright or inverted? (e) Are the object and image on the same side or opposite sides of the lens? (f) Draw ray-diagram
Where must an object be placed with respect to a converging lens of focal length of 24 cm if the image is to be virtual, erected, and three times as large as the object? (Note: express your result in cm). Draw the ray diagram to indicate the position of the object and the position of the image with respect to the lens. Show steps.
A converging lens L_1 has a focal length of 10 cm. A 5cm tall object is located 15cm to the left of L_1. Construct a ray diagram indicating the position and vertical orientation of the image produced by lens L_1. Calculate this position and see that it matches your diagram. A diverging lens L_2 with a focal length of -20 cm is placed 40cm on the right of lens L_1. The image in (a) above now serves as the object...
1 A converging lens with a focal length of 12.2 cm forms a virtual image 7.9mm tall, 11 2emto right of the lens. a. Determine the position of the object. b. Determine the size of the object. Is the image upright or inverted? Are the object and image on the same side or opposite sides of the lens? c. d. 2 You want to use a lens with a focal length of magnitude 36cm with the image twice as long...
A converging lens has a focal length of 6.0 cm A.) Locate the position of the images for the object distance of 4.0cm B.) Find the height of the image of an object 1.0 cm high C.) State whether the image is real, virtual, upright, or inverted D.) Draw a detailed and proportional ray diagram for this situation
An object arrow 2 cm high is placed 20 cm from a converging lens of focal length of 10 cm. Find a) The location of the final image, b) the nature of image, c) the magnification and height of the image. d)Draw a ray diagram of the image formation Using the same lens, work out the results for an Object distance of 8 cm. Answer Parts (a) through (d) as in problem
A converging lens has a focal length of 7.5 cm. An object is placed 5 cm from the lens. a. Draw the rays tracing diagram to locate the image. Is the image real or virtual? b. Calculate the location and the magnification for this image.
Find the focal length of a converging lens that produces a focused real image 3 cm from the lens of an object that is 7 cm from the lens. Draw a ray diagram for this configuration.