Question

A converging lens with a focal length of 12 cm produces a 3-cm high virtual image of a 1-cm high object. Which entry in the table below is correct? image distance location of image A) 8 cm same side of lens as object B) 8 cm opposite side of lens from object C) 12 cm opposite side of lens from object D) 24 cm opposite side of lens from object E) 24 cm same side of lens as object (Draw a neat ray diagram to check your work)

Answer 1

Given focal length of the lens is f= 12cm size of obsect=cn size of inage - 3cm. 3cm 1am Magnification obiect Image of of the lens is given as M = -(size of the image wise of the object ) = 2 2 - 3 do 2-120 to let distance from object bo - distance from image then Mi -10) 3 twe know that, & - - - 2 + 160 to Too gelen 6.- 2f = -2 (12) = -24 cm > bo-- 24cm Negative sign indicates same side of the object and the street and the image is at a distance of 24cm