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Que (2 In a media characterised by, o = 0, y = H, E = 2€, and E = 40sin(27x10t + kz)ay a) State the direction of wave propaga
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Answer #1

The media is characterised by \sigma =0, \mu =\muo and \epsilon =2\epsilono

The electric field is given as

E=40sin(2\pi*106t+kz)ay

a) Since the electric field has a phase given by kz, the direction of propagation along the Z-axis

b) i) The electric displacement is given as D=\epsilonE

D=80\epsilonosin(2\pi*106t+kz)ay

ii) k=\omega/c

where \omega =2\pi*106 rad/s (given)

c=velocity of light=3*108m/s

Thus, propagation vector k=2\pi*106/3*108=2.09*10-2 /m

iii) k\timesE=-\omegaB

Thus,

B=k\timesE/\omega=2.09*10-2 az\times40sin(2\pi*106t+kz)ay/(2\pi*106)=13.33*10-8sin(2\pi*106t+kz)ax

iv) Magnetic intensity H=B/\mu=13.33*10-8sin(2\pi*106t+kz)ax/(4\pi*10-7)=0.11sin(2\pi*106t+kz)ax

c) First Maxwell's equation is \bigtriangledown .E=0 or k.E=0

Since k and E are perpendicular to each other, Maxwell's 1st equation holds true.

Second Maxwell's equation is \bigtriangledown .B=0 or k.B=0

Since k and B are perpendicular to each other, Maxwell's 2nd equation holds true.

d) In phasor form, the electric field can be written as E=Eoej(kz-\omegat)

where the term in the brackets in the exphonent gives the phase of the E-field

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