The media is characterised by =0, =o and =2o
The electric field is given as
E=40sin(2*106t+kz)ay
a) Since the electric field has a phase given by kz, the direction of propagation along the Z-axis
b) i) The electric displacement is given as D=E
D=80osin(2*106t+kz)ay
ii) k=/c
where =2*106 rad/s (given)
c=velocity of light=3*108m/s
Thus, propagation vector k=2*106/3*108=2.09*10-2 /m
iii) kE=-B
Thus,
B=kE/=2.09*10-2 az40sin(2*106t+kz)ay/(2*106)=13.33*10-8sin(2*106t+kz)ax
iv) Magnetic intensity H=B/=13.33*10-8sin(2*106t+kz)ax/(4*10-7)=0.11sin(2*106t+kz)ax
c) First Maxwell's equation is .E=0 or k.E=0
Since k and E are perpendicular to each other, Maxwell's 1st equation holds true.
Second Maxwell's equation is .B=0 or k.B=0
Since k and B are perpendicular to each other, Maxwell's 2nd equation holds true.
d) In phasor form, the electric field can be written as E=Eoej(kz-t)
where the term in the brackets in the exphonent gives the phase of the E-field
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