Question

12.5V, R, S, R, 480 A) 4.87 W 90.781 W C) 1.46 W D W DW 418W G) 105 W 3W 3) in the circuit to the right, an ideal battery, co
0 0
Add a comment Improve this question Transcribed image text
Answer #1

3) {= 12.5 R,= 252 R₂ =4802 R4 48 it 25 E 2 49c2 Iz 12.5 49 25 X 12.5 49 V₂ 248 12.5 ha = 300 49 V 2 Pa 11 1300 49 (300)? (49

Add a comment
Know the answer?
Add Answer to:
12.5V, R, S, R, 480 A) 4.87 W 90.781 W C) 1.46 W D W DW...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • 4) In the circuit for problem 3, one of the resistors R2 is removed from the...

    4) In the circuit for problem 3, one of the resistors R2 is removed from the circuit so that the circuit just becomes R1, the other Rz, and the battery in series. Relative to the circuit in problem 3, the power dissipated in the remaining Ry will: (See answers on the other pages.) R W + 5) What is the total current through the battery for the circuit shown? Ra ww R3 w 루 W R2 4) A) Increase, the...

  • 3) In the circuit to the right, an ideal battery, E, is connected to three resistors...

    3) In the circuit to the right, an ideal battery, E, is connected to three resistors as shown. R1 ε R2 w R₂ What is the power dissipated in each of the resistors, R2? (This is the power dissipated in each individually, not the sum of the two.) 3) E = 12.5 V, R = 252, R2 = 482 A) 4.87 W B) 0.781 W C) 1.46 W D) 1.93 W E) 6.58 W F) 4.18 W G) 1.05 W...

  • Question 1 25 pts Series Parallel Circuit R=200 10V Rz=300 Ry=500 R=200 1. Calculate the total...

    Question 1 25 pts Series Parallel Circuit R=200 10V Rz=300 Ry=500 R=200 1. Calculate the total resistance of the circuit 2. Calculate the current delivered by the battery 3. 3. Find the voltage drop across R4 4. Calculate Power dissipated in 20 ohm resistor

  • a. 1.25w b. 2.0 w c. 12.5 w d. 6.25 w e. 8.13 w The circuit...

    a. 1.25w b. 2.0 w c. 12.5 w d. 6.25 w e. 8.13 w The circuit shown in the figure below contains three resistors (R1, R2, and R3) and three batteries (VA, VB, and Vc). The resistor values are: R1=2 Ohms, R2=R3=4 Ohms, and the battery voltages are VA=25 V, VB=15 V, and Vc=20 V. When the circuit is connected, what will be the power dissipated by R1? Vc HE R1 나와 VA VB R₂ M R3

  • A circuit is constructed with five resistors and one real battery as shown above right. We...

    A circuit is constructed with five resistors and one real battery as shown above right. We model. The real battery as an ideal emf V = 12 V in series with an internal resistance r as shown above left. The values for the resistors are: R = R3 = 40 N, R4 = Rs = 80 and R2 = 142 N. The measured voltage across the terminals of the batery is Vbattery = 11.41 V. I R R R R4...

  • Multiple Choice (6 pts each) 1. An air filled capacitor consisting of two parallel plates separated...

    Multiple Choice (6 pts each) 1. An air filled capacitor consisting of two parallel plates separated by a distance d is cons battery of constant voltage V and acquires a charge Q. While still connected to the ba slab of dielectric with 3 is inserted between the plates of the capacitor. What happe the capacitance and charge on the capacitor? Capacitance a) Increase b) Decrease c) Increase d) Decrease e) Increase Charge Stay the same Stay the same Increase Decrease...

  • R (11%) Problem 24: A circuit consisting of 5 resistors is shown in the graph. Their...

    R (11%) Problem 24: A circuit consisting of 5 resistors is shown in the graph. Their resistances are R; = 19 2, R2 = 75 2, R3 = 892, R4 = 642, and Rs = 262, and the emf of the battery is e = 1.5 V. Suppose the internal resistance of the battery is zero. RI R: R R A 14% Part (a) Express the equivalent resistance of the combination of R2, Rz, and R. Reg Grade Summary Deductions...

  • Problem 1 R=10012 E15 VI C=60 F R=20012 C-40F R-150K In the figure above, two capacitors...

    Problem 1 R=10012 E15 VI C=60 F R=20012 C-40F R-150K In the figure above, two capacitors and three resistors are connected to a 15 V battery as shown. At t=0, switch S is closed. What is the (a) equivalent capacitance, (b) equivalent resistance and (c) time constant of the circuit. At t=5.0 s, calculate (d) the current through the battery, and (e) charge on C. Problem 2 Consider the following circuit, 3 batteries with EMF: E1 = 6 V, E2...

  • Calculate the numerical value of P in W. Total Resistance is 84.2 Ohms and Current is...

    Calculate the numerical value of P in W. Total Resistance is 84.2 Ohms and Current is 0.08907 A. Homework H10 Begin Date: 3/12/2017 12:00:00 AM-Due Date: 3/27/2017 6:00:00 PM End Date: 3/29/2017 12 00:00 AM (0%) Problem 2: A circuit consisting of 5 resistors is shown in the graph. Their resistances are R 18 o. R2 952, R 81 Q. R4 720, and R 39 and the emf of the battery is E .5 v Suppose the intemal resistance of...

  • A circuit is constructed with five resistors and one real battery as shown above right. We...

    A circuit is constructed with five resistors and one real battery as shown above right. We model. The real battery as an ideal emf V = 12 V in series with an internal resistance r as shown above left. The values for the resistors are: R1 = R3 = 22 Ω, R4 = R5 = 82 Ω and R2 = 147 Ω. The measured voltage across the terminals of the batery is Vbattery = 11.6 V. A circuit is constructed...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT