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Conduct a statistical test at a significance level of 0.05 to determine if there is an association between gender and movie p
Blank #3: Ho: There is not) an association between gender and movie preference. (is or Blank #4: HA: There an association bet
Blank # 1 Blank # 2 Blank # 3 Blank #4 Blank # 5 Blank # 6
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Answer #1

Answers:

Blank#1 = Chi-square test of association

(Since, chi square test of association is used to check association between two categorical variables)

Blank#2 = 14.4

( Since, expected count of female who prefer comedy =(Total female × total count of comedy)/Total count

=(80×36)/200 = 14.4 )

Blank#3 = is not

( Since,null hypothesis is, Ho: There is not an association between gender and movie preference)

Blank#4 = is

( Since,alternative hypothesis is, Ha: There is an association between gender and movie preference)

Blank#5 = do not reject

(Since, p-value= 0.129767 Here, p-value > 0.05 ,do not reject Ho )

Blank#6 =does not favours

(Since, we do not reject Ho and conclude that there is not an association between gender and movie preference)

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