Equivalent force at C
clockwise negative x axis means force in - x direction is positive and in + Y direction is positive
now forces in x direction 45 lb , -Fcosa = -25cos52 = -15.3915 lb
Net forces in x direction = 45-15.3915 = 29.608 lb
forces in y direction -10 + 25sin52 = 9.700 lb
so resultant force = sqrt(9.7002 + 29.6082 )= 31.1565 lb Ans
angle with -x axis = taninv(9.700/29.608) = 18.139 degrees Ans
Resultant Couple (assume anticlockwise positive) = 144+10*L- Fsin(52)*0-Fcos52*d= 180.8767 lb in Ans
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