Question

Use the ven Wormation to find the minimum required to make an unknown population means How many wes of data must be randomly
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Answer #1

Given

Confidence Interval = 95%

So Level of Siginfcance = \alpha = 5% = 0.05

Therefore

Z_{cri} = Z_{\alpha } = Z_{5\%} = Z_{0.05} = 1.96

Given Marginal Error = E_{\alpha } = 200

Population S.D = \sigma = 1300

We know that

E_{\alpha } = S.E(\bar{x})*Z_{cri}

\Rightarrow E_{\alpha } = \frac{\sigma }{\sqrt{n}}*Z_{cri}

\Rightarrow \sqrt{n} = \frac{\sigma*Z_{cri} }{ E_{\alpha } }

\Rightarrow \sqrt{n} = \frac{1300*1.96}{ 200}

\Rightarrow \sqrt{n} = 12.74

\Rightarrow n = (12.74)^{2}

\Rightarrow n = 162.3076

\therefore \: \: \: n = 163

OPTION (a)

NOTE: To See the Critical Values of Z; we use the Standard Normal area tabulated values which i posted below.

How to see?

If alpha = 5% the confidence interval = 95% Or Vice Versa

Divide the value 95 with 100. you will get 0.95 and after that divide the value 0.95 with 2; you will get 0.475. Now Search this 0.475 in side the table ( repeating again see inside the table). You will find this at the intersection of (1.9, 0,06) which is Zcri value i.e 1.96.

Like this you can find the Zcri for any alpha values.


Normal Distribution Table a 0.00 0.01 0.02 0.03 0.04 0.05 0.06 0.07 0.08 0.09 0.0 0.0000 0.0040 0.0080 0.0120 (0.0160 0.0199

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