Solution:
Given that, x̄= 98.2°F, S= 0.62°F ,n=109
(1–α)%=99%
α=0.01
α/2=0.005
t(α/2),(n-1)=t(0.005),(108)
= 2.622 ....from student t table.
Margin of error=E=t(α/2),(n-1)×(S/✓n)
=2.622 ×(0.62/✓109)
=2.622 × 0.0594
= 0.1557
Margin of error=E=0.1557
99% confidence interval for the estimate of mean body temperature
of all healthy human is given as,
x̄± Margin of error
=(98.2-0.1557,98.2+0.1557)
=(98.0443,98.3557)
=(98.044,98.356) ... Upto 3 decimal place.
The confidence interval estimate for the population mean μ is
98.044°F<μ<98.356°F
B) This suggests that the mean body temperature is significantly
lower than 98.6°F
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