Question

A data set includes 105 body temperatures of healthy adult humans having a mean of 98.7°F and a standard deviation of 0.64°F. Construct a 99% confidence interval estimate of the mean body temperature of all healthy humans. What does the sample suggest about the use of 98.6°F as the mean body temperature? Click here to view a t distribution table. Click here to view page 1 of the standard normal distribution table. Click here to view page 2 of the standard normal distribution table. What is the confidence interval estimate of the population mean u? 1°F<u< 1°F (Round to three decimal places as needed.) What does this suggest about the use of 98.6°F as the mean body temperature? A. This suggests that the mean body temperature could very possibly be 98.6°F. B. This suggests that the mean body temperature is significantly higher than 98.6°F. OC. This suggests that the mean body temperature is significantly lower than 98.6°F.

Answer 1

Criven The sample size . n = 105 is > 30. So ve Use L-SCOTC. ix 98.7° F B. : 0.64°F (1-w7100% confidence interval for population mean 4 is (7-246). +() I-a (1-0) 100 = 99 : 99 TOL I-=0.99 d = 1.0.99 : 0.01 0.01 2 = 0.005 220.005 = 2.576 "The 99% confidence interval for populalior mean IS [.98.7 = (2-876xl ou ).987+(2-576x| 0.64 105

(98.7 -0.1609 , 98.7 +0.1609) ( 98.5 29 98.861) The 99% confidence interval for the population ( 48.539 98.861) mean el IS >

Cb) Suppose we took more Samples of 105 people. Since 98.6 °F is include in ouy confidence Intervaly hle can expect that 99% of such samples will include an average of 98.6 °F. :.99% confidence interval of the population mean is ( 98.539, 98:861) Therefore This suggests thal the mean body Temperature could very possibly be. 98.6°F :