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6. Given the probability distribution below, find Mean and Standard deviation. X P(x) 0 0.10 10 0.50 20 0.05 30 0.35 Total 1.
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Pin) 0:10 10 Oso 20 0.05 0.35 30 Mean ECM) = Enip(n) 2) Mean (0X0.10)+ (10 x0.50) + ( 20 X 0.05) + (20 X 0.35) sot 5 + 1+ losVar(x) = 385 (16.5)2 385 - 272.25 (1 112.75 standard deviation. √ 112.75 10.618 E 10. 62

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6. Given the probability distribution below, find Mean and Standard deviation. X P(x) 0 0.10 10...
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