After 6 readings an individual is found to have an average red blood cell count of 25 with a sample standard deviation of 5 for a single reading. Assume that counts follow a normal distribution. A normal count is 28. Test the hypothesis that the individual is below average.
Data Summary
Sample Size (n) | Mean (X̅ ) | Standard Deviation (s) | |
Blood count | n = 6 | X̅ = 25 | s = 5 |
The null and alternative hypotheses are
Ho : μ = 28
Ha : μ < 28
where μ is the population mean blood count
Let the level of significance α = 0.05
We use single sample T test since population standard deviation is
unknown, and sample size is small
This is a left tailed test
Using the given formulae, we get
Degrees of
Freedom
df = n - 1 = 6 - 1
df = 5
t-statistic
t-statistic = -1.4697
P-value
For t = -1.4697, df = 5 we find the left tailed p-value using t
tables or Excel function t.dist
p-value = t.dist(-1.4697, 5, TRUE)
p-value = 0.1008
Decision
0.1008 > 0.05
that is p-value is greater than α.
Hence we DO NOT Reject Ho.
Conclusion
There does not exist enough statistical evidence at α = 0.05 to
show that the individual is below average
that is,
The individual is not below average.
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