Question

Large samples of women and men are obtained, and the hemoglobin level is measured in each subject. Here is the 95% confidence interval for the difference between the two population means, where the measures from women correspond to population 1 and the measures from men correspond to population 2: - 1.76 g/dL<H1 - H2 < -1.62 g/dL. Complete parts (a) through (C) below. a. What does the confidence interval suggest about equality of the mean hemoglobin level in women and the mean hemoglobin level in men? it appears that there V a significant difference between the mean level of hemoglobin in women and the mean level of hemoglobin in men. Because the confidence interval (Type an integer or a decimal. Do not round.) b. Write a brief statement that interprets that confidence interval. O A. There is 95% confidence that the interval from - 1.76 g/dL to – 1.62 g/dL actually contains the value of the difference between the two population means (H1 - H2) O B. There is 95% confidence that the difference between the two population means (11 -H2) is either – 1.76 g/dL or - 1.62 g/dL. O C. There is 95% confidence that the difference between the two population means is not 0. OD. There is 95% confidence that the interval from – 1.76 g/dL to - 1.62 g/dL does not contain the value of the difference between the two population means (44 - H2). c. Express the confidence interval with measures from men being population 1 and measures from women being population 2. Choose the correct answer below. A. - 1.76 g/dL<py-< -1.62 g/dL OB. -1.62 g/dL<H1 - H2 < 1.76 g/dL O C. 1.62 g/dL<H2-H2 < 1.76 g/dL OD. - 1.76 g/dL<H1 - H2 < 1.62 g/dL Click to select your answer(s). ?

Answer 1

(a) Because the confidence interval doesn't include 0, it appears that there is a significant difference between the mean level of hemoglobin in women and the mean level of hemoglobin in men.

(b) Option(A): There is 95% confidence that the interval from – 1.76 g/dL to – 1.62 g/dL actually contains the value of the difference between the two population means (μ1 – μ2).

(c) Option(C): 1.62 g/dL < μ1 – μ2 < 1.76 g/dL