Question

Chapter 6, Problem 6/101 Multistep

Determine the range of mass m2 for which the system is in equilibrium. The coefficient of static friction between the block and the incline is μ1 = 0.30 and that between the cord and the fixed disk on the block is μ2 = 0.20.

12 Іш 18 11 m2

m18 T 180 μ,Ν m2 8 N
The Free-Body diagram of the block is shown. Solve for m2 (the lower limit) in terms of m1.

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Answer #1

Solutieo:- diagram mig T FEMIN Free body Consido that block is moving up Terision the Cable mag - eMaß =) T= TA N in UN mag TD) 2012 (72xud horizontal force equilibrium Efx=0 TAMIN-(migt. mag) sin 18° = 0 (48) mag t + j( (mit m2) g casigo) -(m, tm2)

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