Question

9. As shown in Figure 5.30, the jet flow of water with flow rate Q and diameter d is angle θ.

Is hitting the stationary plate of. Find the force and the direction required to support this stationary plate. Also, find Q1, Q2, and F when θ = 60°, d = 25 mm, and Q = 0.12 m3/s.

with explaination please

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Answer 1

Q, a 90- o F V21 2 Güven :-8-60 , d-25mm ;Q=0.12m3/s. Solution By may conservation Q-Q,+Q2 This can be solved by momentum conservation: In or F= mvsino polemesine 1000x 6-12)2 x Sin 6o. N(25X10-3)2 F= 25.405 KN Also > Qcoso - Q1 +02=0 Q-Q,+Q2 of Q=Q1+02 Jousing a sino. for water =fQ² 25405. 24 3=100016g/m3 4 Q = Q caso + O2 Q- Qcoso + Q2+Q2 Q- QA0 - 202 Q [1-105o = 202 a [1-1080] =Q2 2 Also Q=Q4Q2 2 Q = 017[10-coso] > Q = Q- Co-coso]

2 Q;=0-2 +0056 = o[ 4.76050] Cheso] Now substitute values Q1 = @[1+650) - 0-12 0:12 C1+603 60] =0.09m3/s. Az = [1-6050] = 0.12.6-c0360] = 0-12X0.5 -0-03mls Answer F = 25-405%N 0,=009m3/s 02-0.03m3)s. Explanation Cavote! - please check the diagram at first page] to understand. If you resolve o as you asino Queso 4 Q2 outs along sama deréction + QT is a QOS0 +02-4,20 Alo How Conservation so @=Q1+Qz Using than two equation we can find Q, & Q2 F com easily found by momentum conservation. F= osino xfv) Please upvote can , 0 Toceso opposite az In deagram 2 Loult please comment.