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Question Help rou jp OCE In a survey of 3053 adults aged 57 through 85 years, it was found that 89.5% of them used at least one prescription medication. Complete parts (a) through (c) below. a. How many of the 3053 subjects used at least one prescription medication? Round to the nearest Integer as needed.) b. Construct a 90% confidence interval estimate of the percentage of adults aged 57 through 85 years who use at least one prescription medication. om at's (Round to one decimal place as needed.) c. What do the results tell us about the proportion of college students who use at least one prescription medication? O A. The results tell us that, with 90% confidence, the probability that a college student uses at least one prescription medication is in the interval found in part (b). OB. The results tell us nothing about the proportion of college students who use at least one prescription medication OC. The results tell us that, with 90% confidence, the true proportion of college students who use at least one prescription medication is in the interval found in part (b). OD. The results tell us that there is a 90% probability that the true proportion of college students who use at least one prescription medication is in the interval found in part (b)

Answer 1

1.

a) The number of the 3053 subjects used at least one prescription medication is 3053*0.895 = 2732

Answer: 2732

b) 90% Confidence interval:

We need to construct the 90% confidence interval for the population proportion. We have been provided with the following information about the sample proportion: Sample Proportion = 0.895 N = 3053 The critical value for a = 0.1 is ze = 21-a/2 computed as shown below: 1.645. The corresponding confidence interval is p(1-P) p(1-P) CI(Proportion) P - 24V - P + ze v n n 0.895 - 1.645 x 0.895(1 – 0.895) 3053 0.895 +1.645 x 0.895(1 – 0.895) 3053 9 (0.886, 0.904)

c) Correct answer: Option (C)

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2) From Standard normal table, Z_0.85 = 1.036

The indicate IQ Score, X is Mean + 1.036 SD = 100 + 1.036*15 = 115.54

Graph:

Distribution Plot Normal, Mean=0, StDev=1 0.4 0.3 0.85 Density 0.2 0.1 0.0 1.036 0 х

Answer: 115.5