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An box is sitting on a surface with a coefficient of friction of 0.6. A force of SON at 20° with respect to right horizontal)
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Answer #1

Normal force Fu Fsin 20°+mg 50N 50 SM 2014 = 50x sinzo° +5x9.a 50 cos20 = 17.10 +49 Fur 4220 Fu = 66.10 N Upward direchion N

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