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Problem point Consider the new system and the grand eigen vector for the court , and- Finder on the room 3y + 2y --- (0) (0)
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problem 5 å Consider the Linear system 3=1327 3 -5-3 ] find the vectors eigen value and eigen for the coefficient matrix. Q=therefor (A-2) a = 0 -) 3-i 2 [s (3) -3-1 2 (3-1) + 2 U₂ = 0 -501 + (-3-1) V2 = 0 choose V=2 I =-3ti 2 -3ti therefore the eig=) -54,- 372 132 A= is and U2= where ie si = 24 cost + 2q sint the given system mi- 34,+29 the Coefficient me natrix corespon- ) - 5 = – 39 te C2 = – 5 +39 =) - - 5+ 3x3 (9-3) - 5+9 = -2 C2 = 4 therefore the required solution gilt = 2x3 Cost +2x4 sineigen value a-3, Q2 = -3 which is repeated eigen the eigen value a=-3 corrsponding eigen vector e then Now AC =ae - (A-2) e=0Hence the Required General solution est (D) : [< (4) +c7(4)t + (8)}]2 they ay(t) = -3t (6 + (t+1] eze and h(t) (-9 - Gt) est

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