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Question

Question

Answer 1

Answer #1

Given that, mean = 0 and standard deviation = 1

Let X ~ N(0, 1)

We want to find, the value of x such that, P(X < x) = 0.409

P(X < x) = 0.409

$=> P(\frac {X - \mu}{\sigma} < \frac { x -0}{1}) = 0.409$

$=> P(Z< \frac { x -0}{1}) = 0.409$

$=> \frac { x -0}{1}= Z_{0.409}$

$=> \frac { x -0}{1}= -0.23$

=>x=( -0.23*1) + 0

=>x= -0.23

Therefore, required value is -0.23

Answer 2

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