Question

If a projectile is fired with an initial velocity of vo meters per second at an angle a above the horizontal and air resistance is assumed to be negligible, then its position after t seconds is given by the parametric equations x = (vo cos(a)t y = (vo sin(a)t - +- 1012 where g is the acceleration due to gravity (9.8 m/s2). (Round your answers to the nearest whole number.) (a) If a gun is fired with a = 30° and vo = 500 m/s. When will the bullet hit the ground? How far from the gun will it hit the ground? m What is the maximum height reached by the bullet? m (b) Find the equation of the parabolic path by eliminating the parameter.

Answer 1

a 9 given Vo=600 m/s x = 30° to find Time of flight T = ? TE alo.sind using formula. 9 1 = (2)6600).sin30 = 61.2 sec (Answer) 9.8

(2) Range R = vo sinza g R : [600) Sin (2x30) 9.8 R: 31813 m R: 31813 m (Answed) 3) 2 Manimum height H= Vo V sinha 29 H = [6ool sin 30 (2)(9.8) H: 4592 m. 5 equation of Parabolic Path. g x y = (tand) x 2v² cost