P. The horizontal distance of a projectile (in feet) is given by x (vo cos e)t,...
Consider a projectile launched at a height h feet above the ground and at an angle θ with the horizontal. If the initial velocity is v0 feet per second, the path of the projectile is modeled by the parametric equations x = t(v0 cos(θ)) and y = h + (v0 sin(θ))t − 16t2. The center field fence in a ballpark is 10 feet high and 400 feet from home plate. The ball is hit h = 2 feet above the...
At moment of time t=0 a projectile is fired directly upward with an initial velocity 192 ft/sec, and initial height 200 ft. Find: a)velocity and acceleration after t seconds, (b) velocity when projectile hits the ground, (c) time of travel from the highest point to the ground. Equation of motion is h"= -32, where h(t) is the height of projectile at moment t.
A projectile is thrown upward so that its distance, in feet, above the ground after t seconds is h= -16t2+608t. What is its maximum height?
box the answer thank you Step 1 Use the following model for projectile motion to write the vector function that describes the path of the bomb at an altitude 33,500 feet, initial velocity of 540 mi/h, and an angle of elevation 0 0. r(t) (vo cos 0)ti +(vo sin e)t + initial velocity initial height e= angle of elevation acceleration due to gravity Vo h = =32 ft/sec Substitute the given values accordingly and simplify. Note: Remember to convert units...
If the projectile is launched at a launching angle theta, with an initial velocity Vo from a height of Yo above the table top, how long does it take the projectile to fall on the table top? Now that your Voy is no longer zero, so you must use the quadratic equation to solve for t. Express the time in terms of g,Yo,Vo, and theta, make sure that your y-direction is fixed. t= How far would it travel? Express in...
A projectile is launched straight up from ground level with an initial velocity of v0 per sec. Neglecting air resistance, its height in feet, s, after t seconds after launch is given by the equation s = –16t2 + v0t. At what time(s) will the projectile reach a height of 112 feet when v0 = 96 feet/sec? After how many seconds will it return to the ground when v0 = 96 feet/sec?
using parametric equations and ange 6. Chris and Linda are standing 78 feet apart. At the same time, they each throw a softball toward each other. her ball with an initial velocity of 45 ft per second with an angle of inelination of 44. Chris throws her ball with an initial velocity of 41 feet per second with an angle of inclination of 39 a. Find two sets of parametric equations that represent a model of the problem situation. b....
Fill in the Blanks A golf ball is projected upward from ground level at an initial velocity of 112 ft/sec. The height of a projectile can be modeled by s(t) = -16t+ vot + So, where t is time in seconds, So is the initial height in feet, and Vo is the initial velocity in ft/sec. a. How high will the ball be after 2 sec? O feet b. What is the maximum height the ball reaches? O feet c....
If a projectile is fired with an initial velocity of vo meters per second at an angle a above the horizontal and air resistance is assumed to be negligible, then its position after t seconds is given by the parametric equations x = (vo cos(a)t y = (vo sin(a)t - +- 1012 where g is the acceleration due to gravity (9.8 m/s2). (Round your answers to the nearest whole number.) (a) If a gun is fired with a = 30°...
10) An object is propelled upward at an angle e, 45° << 90°, to the horizontal with an initial velocity of vo feet per second from the base of a plane that makes an angle of 45° with the horizontal. If air resistance is ignored, th distance R that it travels up the inclined plane is given by the function vo22 R(O) = [sin(20) - COS(20) - 11. 32 Show that v02/2 R(O) = [sin (cos 0 + sin o)...