Question

The contingency table shows the results of a random sample of former smokers by the number of times they tried to quit smoking before they were habit-free and gender. At a = 0.10, can you conclude that the number of times they tried to quit before they were habit-free is related to gender Perform the indicated chi-square independence test by completing parts (a) through (e) below. Number of times tried to quit before habit-free Gender 2-3 4 or more 272 257 151 Female 145 138 79 Male (a) Identify the claim and state Ho and Ha Ho: The number of times former smokers tried to quit Ha: The number of times former smokers tried to quit Which hypothesis is the claim? O Alternative hypothesis Null hypothesis O (b) Determine the degrees of freedom, find the critical value, and identify the rejection region. Calculate the degrees of freedom. d.f.= Find the critical value. xo - (Round to three decimal places as needed.) Click to select your answer(s).

Answer 1

Solution:

a) Test hypothesis:

H0: The number of times they tried to quit before they were​habit-free and​ gender are independent

H1: The number of times they tried to quit before they were​habit-free and​ gender are dependent

Claim: Null Hypothesis

b) Degree of freedom = 2

Chi square Critical value(X²): 4.6051

X² static < X² critical Option D

c)

Chi-Square Calculator - Results Observed Expected Chi-Square Component Categories O; Ei (0;- Ej)2 / E; Category 1 272 272.13 0.0001 Category 2 257 257.774 0.0023 Category 3 151 150.096 0.0054 Category 4 145 144.869 0.0001 Category 5 138 137.226 0.0044 Category 6 79 79.904 0.0102 Total: 1042 1041.999 0.0225

Test statistic(X²) = 0.02253

d) Since X² static is less then X² critical,

Fail to  reject H0

e) is not , is independent of gender