Question

Please, I need help answering questions 10, 11, 12, 13, 14, and 15. Use the other pages as information to solve the questions.

Use the questions below to keep track of key concepts from this lesson's study activity. YOUR ASSIGNMENT: Splatapults Away! The engineering club has built a catapult and wants to test it out. The local supermarket has donated some overripe fruits and vegetables, and now the club is holding a Splatapult challenge to see who can hit the most targets. The catapult can launch food pretty far and make a real mess! In order to hit a target and win the Splatapult challenge, you'll need to aim the catapult just right. Use the Graphing Tool and your knowledge of quadratic functions to help you model the flight paths of the different projectiles and hit the target. Organize your information 1. Which fruit or vegetable did you select? List the information you know about its path. (2 points: 1 point for the selection, 1 point for the values) The vegetable that I chose was the pumpkin the target is soft away. In order to travel that for the pumpkin needs to have a maximum height of 62ft. 2. Your fruit or vegetable will follow a parabolic path, where x is the horizontal distance it travels (feet), and y is the vertical distance (feet). a) The x-intercepts are the places where your fruit or vegetable is on the ground. The first x-intercept is (0,0). The second x-intercept is where the fruit or vegetable hits the ground after it's launched. What are the coordinates of the second x-intercept? (2 points: 1 point for each coordinate) ps://course apelearning.com/public/pop/3/7/5/3036160 Page 1 of 2

Answer 1

(010) 1 I am not carrying a laptop currently. if you follow the u Steps, will find the required parabola very easily. But, believe giren you will LLLLLLLLLL It would come mean to- Y -0.0992 () (6-50) Another equation y. - 16d 2 of rot 3 when Difference between these & two egas şeo 03 Rao is the location of parabolic car of the the projectile fire and y}, n denotes the horizontal / ground distance, while y denotes the height of the projectile eq i is the parabolic ear of ega ble height the projectile (y) and time (a), the height of the motion at particular time. where a can get find out the height can Similarities In both the equations, of the progectile. in ega » By putting By putting value of value of + lairen чS 12 vo ear ☺ becomes y = -16d2 + 454 at 6 G go for Height (y) ti! y : - 168 (1) 2 & 45x (1) a G 35 feat Y, t-2 ५ - 168 (9g2+ 45% (2) at 6 32 feet

Qq? y. -164² a 451 & 6 for renden Puy dy + . 16 x 24 45.0 1.40 625 45 Put value of in the ea -IG (1.40625)+ 45(1.40625) 46 y Y 37.640 625 resten (1.40625 37.640625) ད ད At the senten it'll height achieve tha manimum height 37.640625 feet our en is the 91 form of parabola (1.40625,37.640625) (0,6) 16 to increase All As you yourself found out the desired desined height 62 feet which is greater than in this case (37.640625) clearly we have our initial the desired velocity to achieve height Initial relocity should be greater than 45 per second. so feet