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SUBMITTED Ozonolysis (O3 in CH2C12) of compound A gives formaldehyde and 2-butanone. Catalytic hydrogenation of A...
TO EDIT YOUR WORK AND RE-SUBMI YOU HAVE ALREADY SUCCESSFULLY SUBMITTED YOUR WORK Ozonolysis (O3 in CH2C12) of compound A gives formaldehyde and 2-butanone. Catalytic hydrogenation of A gave compound B. Compound B is likely to be 2-methyl-2-pentene O2-methylpentane pentane O butane 2-methylbutane ! The commundshown hal
Upon catalytic hydrogenation an unknown compound A (C6H12) gives cyclooctane. Ozonolysis of A gives octanedioic acid (HOOC-(CH2)6-COOH). Draw the structure of A.
3. Compound A (C20H18) undergoes hydrogenation to form Compound B. Ozonolysis of Compound A provides the products shown below. What are the structures of Compound A and B? 2 1 + 0
What is the IUPAC name for the organic compound shown below? CH-CH O A. trans-2-pentene B. cis-2-pentane C. trans-2-butene D.2-butane E. cis-2-butene
When the epoxide 2‑vinyloxirane reacts with lithium dibutylcuprate, followed by protonolysis, compound A is the major product formed. Oxidation of A with PCC yields B, a compound that gives a positive Tollens test and has an intense UV absorption around 215 nm. Treatment of B with Ag2O,Ag2O, followed by catalytic hydrogenation, gives octanoic acid. Identify A and B.
Answer all Answer all 4. What is the structure of the compound that gives the IR and proton NMR spectra? Examine the H NMR of each structure as a review. Note the chemical shift for each proton 100 MHz proton NMR spectrum CDC13 solution 2270 IR Spectrum (liquid film) 1745 - 4000 3000 1200 800 TMS 2000 1600 fem') oppm) O HƏNCH:C=c-c-OCH; NEC-CH:-0-OCH:CH; o 1,6--OCH HC --CHÚC H:C-C-OCH:CH.CN H;CCH: -2-0-CH:CN 1. Compound, B, has the molecular formula C7H12. On catalytic...
Problem #23: When compound X (C,H,Br) is reacted with sodium cyanide (NaCN) forms compound Y (C,H,N). Compound Y, upon reduction with H over a Ni catalyst, yields compound Z (C,HIN. The 'H NMR spectrum of X gives two signals, a multiplet at δ = 7.3 ppm (5H) and a singlet at δ 4.25 ppm (2H). The 'H NMR spectrum of Y is similar to that of X in that it shows a multiplet at ö-7.3 ppm (5H) and a singlet...
26) Name the following compound. CH3 H2C=CH-CH2CHCH: A) 1,1-dimethyl-3-butane B) 4-methyl-1-pentene C) hexene D) 2-methyl-4-pentene E) 2-methylpentene 27) Name the following compound. CI A) 2,3,5-trichlorobenzene B) trichlorostyrene C) 1,3,4-trichlorobenzene D) 1,3,4-trichlorohexene E) 1,2,4-trichlorobenzene 28) Identify the formula for an alkene. A) CnH2n+4 B) CnH2n+2 C) CnH2n D) CnH2n-4 E) CnH2n-2 29) Name the following compound. A) 1,4-bromocyclohexene B) 1,4-dibromobenzene C) 3,6-dibromobenzene D) 2,5-dibromobenzene E) 2,5-dibromocyclohexene 30) Name the following compound. CECH CH,CH,CHCH A) 2-ethynebutane B) 3-methyl-1-pentyne C) 3-methyl-4-pentyne D) 3-ethyl-1-butyne...
Chem 210 Report - IR Spectroscopy Name: ID: 1) For the functional group(s) on the following molecule what characteristic IR absorption(s) would be expected (ignoring C-H absorptions). A) a peak around 1700 cm–1 B) a peak around 3300 cm–1 C) a peak around 1650 cm–1 D) a peak around 2250 cm–1 E) None of these choices Answer: 2) An oxygen-containing compound shows strong IR absorption at 1630-1780 cm–1 and 3200-3550 –1 cm . What type of compound is it likely...
Alkene reaction and mechanisms practice exercise 1) O₃ 2) (CH3)2S 25) Treatment of cyclopentene with peroxybenzoic acid A) results in oxidative cleavage of the ring to produce an acyclic compound B) yields a meso epoxide C) yields an equimolar mixture of enantiomeric epoxides D) gives the same product as treatment of cyclopentene with Os04 E) none of the above 26) Provide a detailed, step-by-step mechanism for the reaction shown below. но Br2 na + HBT Br 27) Provide a detailed,...