the reaction is
HSO4-(aq) + HO- (aq) ===> SO42- (aq) + H2O(aq) :
I 0.05 0.03 0.07 0
E 0.02 - 0.10
Since we know that
pka = 1.92
we have for buffers, pH = pKa + log [SO42- ] /[HSO4- ]
As we know wth0.03 moles of OH- added :
[SO42- ]= 0.07 moles + 0.03 moles / L = 0.10 M
[HSO4- ] = 0.05 moles - 0.03 moles / L = 0.02 M
pH = 1.92 + log (0.10/0.02)
pH =1.92+0.69
pH = 2.59
So the correct answer is option (B) 2.59
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